(5x-6)^(1/2)=7

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Solution for (5x-6)^(1/2)=7 equation:


D( x )

5*x-6 < 0

5*x-6 < 0

5*x-6 < 0

5*x-6 < 0 // + 6

5*x < 6 // : 5

x < 6/5

x in <6/5:+oo)

(5*x-6)^(1/2) = 7 // - 7

(5*x-6)^(1/2)-7 = 0

(5*x-6)^(1/2) = -7 // + 7

(5*x-6)^(1/2) = 7 // ^ 2

abs(5*x-6) = 7^2 // - 7^2

abs(5*x-6)-7^2 = 0

x in (-oo:+oo)

abs(5*x-6)

5*x-6 >= 0

5*x-6 >= 0 // + 6

5*x >= 6 // : 5

x >= 6/5

x in <6/5:+oo)

5*x-7^2-6 = 0

x in (-oo:6/5)

6-(5*x)-7^2 = 0

abs(5*x-6)-7^2 = 0

/ | 6-(5*x)-7^2 = 0 i x in (-oo:6/5) | 5*x-7^2-6 = 0 i x in <6/5:+oo)

x in (-oo:6/5)

6-(5*x)-7^2 = 0

-5*x-43 = 0 // + 43

-5*x = 43 // : -5

x = 43/(-5)

x = -43/5

x in <6/5:+oo)

5*x-7^2-6 = 0

5*x-55 = 0 // + 55

5*x = 55 // : 5

x = 55/5

x = 11

x in { -43/5}

x = 11

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